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This footnote is supposed to clarify the hand-waving argument in the main text with the help of simple mathematics and graphic. The first task is to show that there is a minimum for the action S (for a given Lagrangian L as shown in Eq.(49)) as the paths varies between two fit points. The trajectory of the particle is calculated from the equation derived from the "principle of least action" as shown in Eq.(50).
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Figure 11 Paths |
Figure 12 Actions |
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) with m = 1 gm and substituting q, dq/dt from Eqs.(52a,b) (see also Figure 01a). The paths in Figure 11 and the corresponding actions in Figure 12 are computed by varying the parameter "a" from -50 to +50 in step of 10. The path traces out a straight line for a = 0. For particle in free space, i.e., for k = 0, the correspondence of shortest path (a straight line) and least action (when S is at its minimum) is exact. The correspondence is off when interaction is taken into account (for example with k = 1 gm/sec2, a=(kX/2)/[m-(kT2/10)]
0.6 cm/sec2 when S is at its minimum) as if the force field creates a curve space for which the shortest path is not a straight line anymore. Actually, each paths is similar to a numeral devoid of any physical content by itself. They are one step away from the trajectory of a real particle contrary to what some physicists have it interpreted otherwise. Feynman's expression of "sum over paths" in his original work has been altered to "sum over histories" attaching additional meaning as if the paths are real. Furthermore the Lagrangian involved may or may not describe the actual motion of the particle. Additional constraints have to be imposed by demanding invariance under certain operations and it will ultimately be justified by observations.
dq = (mv/2) X = constant
(shortest path) = constant
(actual trajectory) = least action![]() |
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Then along came quantum mechanics and the method of path integral to calculate the transition amplitude between two points, e.g., from ta = 0 to tb = T : ![]() The sum is supposed to include all kinds of paths imaginable. However, for demonstration purpose the family of paths considered in the previous section is |
Figure 13 Path Integral, Real |
Figure 14 Path Integral, Img |
sufficient (see Figure 11). The Planck's constant can also be absorbed into the action S so that the computational procedure can be carried over to evaluate the sum. |
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An alternate way to perform the path integral is to sum over all the paths at different time t and then put them all together as shown in Figure 15, where the time coordinate is divided into N parts of equal interval . Thus T = N , and dt = 0. The transition amplitude <0|X> can be written as :<0|X> = A ![]() ![]() ![]() ![]() e(i / ) L(qn - qn-1)dq1![]() ![]() dqN-1 ---------- (55)where A is the normalization constant. For a particle in free field L = (m/2)(dq/dt)2, A = (m/ih )N/2 Eq.(55) can be evaluated analytically :<0|X> = A ![]() ![]() ![]() ![]() e(im/2![]() ) (qn - qn-1)2dq1![]() ![]() dqN-1= (m/ihT)1/2exp(imX2/2 T) ---------- (56)
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Figure 15 Path Integral |
The integration is carried out by applying the Gaussian integral : e-f(qn-qn-1)2-g(qn+1-qn)2dqn = [ /(f+g)]1/2{e-[fg/(f+g)](qn-1-qn+1)2} ---------- (57)repeatedly (N-1) times. |
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The real part of the transition amplitude <0|X> is plotted in Figure 16 and 17 with T and X holding constant respectively. Figure 16 shows that the wavelength is shorter at large X signifying higher probability for particle with higher velocity to get there. On the other hand in Figure 17 for a given X, a particle with lower velocity (and hence longer wavelength) would take longer to reach. But the chance of getting there becomes progressively smaller. Numerical computation is again performed by a home computer with Basic programming. The electron mass m is assumed in the calculation, thus (m/h)1/2 ~ 0.4 and (m/2 ) ~ 0.5. For the case of constant T, X is evaluated
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Figure 16 X vs Transition Amplitude [view large image] |
Figure 17 T vs Transition Amplitude [view large image] |
within the range -3 to +3 in step of 0.001 (in unit of cm); while for the case of constant X, T is evaluated from 0.5 to 5 in step of 0.0001 (in unit of sec). |
/2m)
<0|x> = i
<0|x> ---------- (59)
in the form of ei(kx-
t) is not connected to any initial conditions but satisfies the same equation as shown in Eq.(59).| X | T | |<0|X>1| | |<0|X>2| | |<0|X>2|/|<0|X>1| | |<0|X>2|/T |<0|X>1| |
|---|---|---|---|---|---|
| 1 | 1.0 | 8.75 | 0.40 | 0.045 | 0.045 |
| 1 | 1.25 | 6.28 | 0.36 | 0.057 | 0.046 |
| 1 | 1.5 | 4.80 | 0.33 | 0.067 | 0.045 |
to +
. Thus, the transition amplitude can be rewritten as:
eiS/
da ---------- (61)
90o from the Minkowskian spacetime to the Euclidean spacetime. The technique alters the oscillating exponential to a decaying exponential making the integration much easier to carry out. Actually, Method 2 has performed the Wick rotations already implicitly.
C e-kx2+fx+gdx = C(
/k)1/2e(f2/4k)+g ---------- (62)
T)
(8.94/iT3/2)exp(imX2/2
T) ---------- (63)
/2m)
<0|x>'3 = i
<0|x>'3 ---------- (64)
0.045 ---------- (65)